Minimum Absolute Difference in BST
Link
Description
Given the root
of a Binary Search Tree (BST), return the minimum absolute difference between the values of any two different nodes in the tree.
Example 1:
- Input:
root = [4,2,6,1,3]
- Output:
1
Example 2:
- Input:
root = [1,0,48,null,null,12,49]
- Output:
1
Constraints:
- The number of nodes in the tree is in the range
[2, 10^4]
.
0 <= Node.val <= 10^5
Solution
Way 1
| /**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
private:
vector<int> inorder;
void traversal(TreeNode* root) {
if (!root) return;
traversal(root->left);
inorder.push_back(root->val);
traversal(root->right);
}
public:
int getMinimumDifference(TreeNode* root) {
traversal(root);
int minVal = INT_MAX;
for (int i = 1; i < inorder.size(); i++) {
minVal = min(minVal, inorder[i] - inorder[i - 1]);
}
return minVal;
}
};
|
Way 2
| /**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
private:
TreeNode* pre;
int res = INT_MAX;
void traversal(TreeNode* root) {
if (!root) return;
traversal(root->left);
if (pre) res = min(res, root->val - pre->val);
pre = root;
traversal(root->right);
}
public:
int getMinimumDifference(TreeNode* root) {
traversal(root);
return res;
}
};
|
- Time complexity: \(O(n)\);
- Space complexity (worst): \(O(n)\).